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x^2=2x-0.75
We move all terms to the left:
x^2-(2x-0.75)=0
We get rid of parentheses
x^2-2x+0.75=0
a = 1; b = -2; c = +0.75;
Δ = b2-4ac
Δ = -22-4·1·0.75
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-1}{2*1}=\frac{1}{2} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+1}{2*1}=\frac{3}{2} =1+1/2 $
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